Dynamically Add Input Form Fields With jQuery

And how to deal with the data on the server-side (PHP)

A very frequent requirement from customers is to have input fields dynamically added to a form while typing in it. This should happen without refreshing the page because the user shouldn't be submitting the form before all their information is completed. Here below is a simple example of such interface:
Item quantity: Item name:

Click on the "Add Row" button and you'll see it in action. Ever wondered how to do something like this? Let me show you.

Download Working Example Here!
(some fixed to the code are added inside)

The HTML

The HTML code for this is actually quite simple. It's just a form with onclick action at the "Add row" button:
<form method="post">
<div id="itemRows">

Item quantity: <input type="text" name="add_qty" size="4" /> Item name: <input type="text" name="add_name" /> <input onclick="addRow(this.form);" type="button" value="Add row" />

</div>
</form>

The JavaScript (jQuery)

If you had to do this with basic Javascript, it would require lots of typing. But the jQuery's html() method takes all the browser-related hassle out of you, so you can just construct your HTML code and append it when the button is clicked:
var rowNum = 0;
function addRow(frm) {
rowNum ++;
var row = '<p id="rowNum'+rowNum+'">Item quantity: <input type="text" name="qty[]" size="4" value="'+frm.add_qty.value+'"> Item name: <input type="text" name="name[]" value="'+frm.add_name.value+'"> <input type="button" value="Remove" onclick="removeRow('+rowNum+');"></p>';
jQuery('#itemRows').append(row);
frm.add_qty.value = '';
frm.add_name.value = '';
}
This function simply constructs HTML code for a new row while filling the form field values from the data supplied by the form. Then it appends the code to the wrapper DIV element and cleanups the values in the original form. Cleaning up the values is good user experience practice in such cases. Otherwise the user will be confused whether the first row will be stored to the database or not. The added rows don't have another "add row" button. Instead of this they have "remove" button in case the user has added too many rows and wants to delete some of them. Here is the removeRow() function:
function removeRow(rnum) {
jQuery('#rowNum'+rnum).remove();
}
Now you can see why we needed to count the rows and to use that rowNum global variable. We needed unique ID on each row so it can be removed.

The Back-End (PHP) - Inserting the records

At the server-side there is a straighforward and a tricky part. I'll show you the easy one first - inserting the data. Let's assume we have a MySQL database and a very simple table called products with fields id, qty and name. So when processing the POST data we'll do something like this:
foreach($_POST['qty'] as $cnt => $qty) {
$sql = "INSERT INTO products (qty, name) VALUES ('$qty', '".$_POST['name'][$cnt]."');";
// run the query - with mysqli_query or whatever database wrapper you are using
// ...
}
(Please note there is no security filtering done in the query above) In case you don't understand, here's the explanation: as the field names had [], in PHP this will send $_POST array with the name of the field and the values from all form fields with this name. So we are iterating through the $_POST array 'qty' while taking the current index in $cnt. Then we use the same $cnt to match the same row value in $_POST['name']. And that's it, the data is inserted.

The Back-End (PHP) - Updating the records

This is where the things become tricky. We have several goals:
  • To let the user see and edit already inserted data
  • To let the user add new data
  • To let the user remove data
This means we have to construct some more HTML and basically break it in two parts - editing existing data and adding new data. The HTML/jQuery code for adding new data will be exactly the same as above. So let's see what can we do with the existing data:
// let's assume you have the product data from the DB in variable called $products
foreach($products as $product):?>
<p id="oldRow<?=$product['id']?>">Item quantity: <input type="text" name="qty<?=$product['id']?>" size="4" value="<?=$product['qty']?>" /> Item name: <input type="text" name="name<?=$product['id']?>" value="<?=$product['name']?>" /> <input type="checkbox" name="delete_ids[]" value="<?=$product['id']?>"> Mark to delete</p>
<?php endforeach;?>
What's going on here? We are iterating through the existing DB records and displaying similar forms for them letting the user edit the data. We also add a checkbox that allows them to mark a product for deletion. All the changes will be stored after the form is submitted. Like this:
// first delete the records marked for deletion. Why? Because we don't want to process them in the code below
if(is_array($_POST['delete_ids']) and !empty($_POST['delete_ids'])) {
// you can optimize below into a single query, but let's keep it simple and clear for now:
foreach($_POST['delete_ids'] as $id) {
$sql = "DELETE FROM products WHERE id=$id";
// run the query - not shown
}
}

// now, to edit the existing data, we have to select all the records in a variable.
$sql="SELECT * FROM products ORDER BY id";
$products = .... // run your DB wrapper methods here to fill $products

// now edit them
foreach($products as $product) {
// remember how we constructed the field names above? This was with the idea to access the values easy now
$sql = "UPDATE products SET qty='".$_POST['qty'.$product['id']]."', name='".$_POST['name'.$product['id']]."'
WHERE id='$product[id]'";
// run the query
}
// (feel free to optimize this so query is executed only when a product is actually changed)
And after the above is done, don't forget to also add the new products with the same code as in "Inserting the records" section. That's it. Was it clear and easy?

A Few Interesting Scripts

Browsing Codecanyon I've found several ready scripts that do something like what I have described above. Have a look at them and decide yourself if some of them can do the work for you:

28 thoughts on “Dynamically Add Input Form Fields With jQuery

  1. admin Post author

    No but you can copy all the sources by clicking on the first icon top right of each of them.

  2. Filippo

    The insert procedure give error as it:
    Warning: Invalid argument supplied for foreach() in ……..

    becasue the post send an array.

    Then need to add, before the first line “foreach…) the follow:

    if(is_array($_POST[‘qty’])) {

    foreach($_POST[‘qty’] as $cnt => $qty) {
    $sql = “INSERT INTO products (qty, name) VALUES (‘$qty’, ‘”.$_POST[‘name’][$cnt].”‘);”;
    … query …
    }
    }

    I not understand why is omitted this. Impossible work without.

    Now i go to see why not insert the records in the data base.

  3. admin Post author

    As the post says, validation and filtering is not shown above for simplicity. You should validate user’s input yourself.

  4. Filippo

    Hello, now work.
    But there is one problem, if i submit only one row give error.

    If i submit more than one row is ok but insert always the rows added but not the first.

    If for example i add 4 more row (in total 5), insert in the database only the 4 row added, always skip the first.

    Why?

    Thanks you.

  5. admin Post author

    Because this code cannot be applied as-is, every case is specific and you need to customize it for your needs. And because this is a tutorial and not a ready code. The goal of tutorials is to learn something, not to copy code and use it without having an idea how it works.

  6. Pingback: Best JavaScript Tutorials, Techniques, Plug-ins and Libraries

  7. Esteban

    Hi, I adapted the code to my site, however I’m having a problem.
    I only use 1 field without adding extra fields, the info won’t get inserted in the database.
    I tried but I don’t know how to fix this.

    Thanks,
    Esteban

  8. David

    I want to display one input box and one select combo box. According to your tutorial, text box is move to down is OK but if i try with select box. it not select our selected value and not move to down. So what i need to change for select box. Let me know reference or changes for this setting.

  9. admin Post author

    Everyone who asks a question or says something doesn’t work, provide URL or at least a piece of code. You can’t expect the others to guess what’s wrong based on an explanation.

  10. Christine

    Hi, for those, like me, who loved this but couldn’t quite figure out how to get the 1st field read into a database etc this is what I did:

    I added 2 hidden fields that mirrored the first form fields with the required name values to be read into the database:

    $( “input:text.edit_number_group_form_phoneNumber” )
    .focusout(function() {
    var text = $( this ).val();
    $( “input:hidden#edit_number_group_form_phoneNumber_1″ ).val( text );
    })
    .focusout();

    so finding the text input with a class of your choice (edit_number_group_form_phoneNumber) once focused out copy the value and put it in the hidden field with the id (edit_number_group_form_phoneNumber_1)

    Hope this helps someone as took me a bit to figure out/find the solution

  11. Rick Williams

    This was an awesome code and really helped me. For those who need the first field values, actually just set my variable to be $_POST[‘add_qty’]. I hope this helps.

  12. ilovemyjourney

    wow, thank you sir
    it’s work!!

    now i have a problem

    can we put jquery autocomplete in here???

  13. Utuh Aslan

    i got problem….after i submit the data…then refresh the browser…..the dat data still keep send into database..how to prevent it

  14. Jeff Roberts

    Thanks for the tutorial. I’m stuck and hoping someone here can help me. I added a few fields and I’m trying to use it in a form that sends an email on submission instead of writing to a database. I am getting the first row of fields no problem, but the variable which is supposed to capture the dynamically created rows only sends the following output:
    Array Array Array Array
    Array Array Array Array

    Here is my code to try and loop to capture the dynamic rows :

    if(is_array($_POST[‘qty’])) {
    foreach($_POST[‘qty’] as $cnt => $qty) {
    $qty_array[]=$qty;
    $title_array[]=$_POST[‘title’][$cnt];
    $page_array[]=$_POST[‘page’][$cnt];
    $price_array[]=$_POST[‘price’][$cnt];
    $myorderrow2 .=”$qty_array $title_array $page_array $price_arrayn”;
    }
    }

    Thanks for any help you can give!

  15. Jeff Roberts

    UPDATE: I finally got it, just after posting this! I was missing the array count:
    $myorderrow2 .=”$qty_array[$cnt] $title_array[$cnt] $page_array[$cnt] $price_array[$cnt]n”;

  16. Zaheer

    how to get limited dynamin fields and how can fix their name for example
    .

    to a=12

    and

    .

    to b=12

  17. Vignesh Raju

    when i’m try to run that msg shows
    Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in C:xampphtdocsvickydynamic-form-fields.html.php on line 61

  18. Vignesh Raju

    after save changes that error shown

    Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in C:xampphtdocsvickydynamic-form-fields.html.php on line 21

    wat can i do …?

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